4x^2-12=58

Solution for 4x^2-12=58 equation:

4x^2-12=58

We move all terms to the left:

4x^2-12-(58)=0

We add all the numbers together, and all the variables

4x^2-70=0

a = 4; b = 0; c = -70;
Δ = b2-4ac
Δ = 02-4·4·(-70)
Δ = 1120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1120}=\sqrt{16*70}=\sqrt{16}*\sqrt{70}=4\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{70}}{2*4}=\frac{0-4\sqrt{70}}{8}
=-\frac{4\sqrt{70}}{8}
=-\frac{\sqrt{70}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{70}}{2*4}=\frac{0+4\sqrt{70}}{8}
=\frac{4\sqrt{70}}{8}
=\frac{\sqrt{70}}{2}
$